College Math CLEP Prep Practice Exam

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Find two consecutive positive numbers whose fourth power sum is 989.

9, 10
10, 11
11, 12
12, 13

The correct answer is: 10, 11

To find two consecutive positive numbers, we need to consider the first number as x and the second number as x+1. For the given question, we have to find x and x+1 such that (x^4 + (x+1)^4) = 989. This can be simplified to 2x^4 + 4x^3 + 6x^2 + 4x + 1 = 989. After solving the equation, we get x=10. Therefore, the consecutive numbers are 10 and 11. Option A (9 and 10) gives a sum of 625, which is not equal to 989. Option C (11 and 12) gives a sum of 1521, which is also not equal to 989. Option D (12 and 13) gives a sum of 2385